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Tighter tension on curve?
3 posts
• Page 1 of 1
Tighter tension on curve?
I am working on a project, and I am trying to get the right curve on the tension. This is the code I have for it.
What I am after is having a "tighter" tension, rather than having it stretch through the whole plot. This is new to me, so I am experimenting as much as I could. Here is a video example of how it looks and also how I want the curve to go: https://www.youtube.com/watch?v=g97tR-IRmdo
Could someone point to the right direction regarding this?
Many thanks!`
- Code: Select all
def curve x, tension
tn = [[0.5 * (tension+1.0), 0.999999].min, 0.000001].max
t = 1.0 - (2.0*tn-1.0) / tn
return (t!=1.0) ? (t**x-1.0) / (t-1.0) : x
end
What I am after is having a "tighter" tension, rather than having it stretch through the whole plot. This is new to me, so I am experimenting as much as I could. Here is a video example of how it looks and also how I want the curve to go: https://www.youtube.com/watch?v=g97tR-IRmdo
Could someone point to the right direction regarding this?
Many thanks!`
- shrunkyq
- Posts: 15
- Joined: Fri Aug 17, 2018 9:21 pm
Re: Tighter tension on curve?
The curve in the video looks like a rational function.
Suppose your x variable goes from 0 to 1.
Suppose you want to map this to y-values from 0 to 1.
Allow the midpoint x=0.5 to map to some y-valute t between 0 and 1.
So you have the following mapping table:
The general mapping formula would be:
y = t*x/(1 - t +(2t - 1)*x)
Obviously for t = 0.5 this results in the trivial mapping y = x as it should.
Suppose your x variable goes from 0 to 1.
Suppose you want to map this to y-values from 0 to 1.
Allow the midpoint x=0.5 to map to some y-valute t between 0 and 1.
So you have the following mapping table:
- Code: Select all
x y
-------
0 0
0.5 t
1 1
The general mapping formula would be:
y = t*x/(1 - t +(2t - 1)*x)
Obviously for t = 0.5 this results in the trivial mapping y = x as it should.
-
martinvicanek - Posts: 1315
- Joined: Sat Jun 22, 2013 8:28 pm
Re: Tighter tension on curve?
Thank you Martin, I will definitely check this out!
martinvicanek wrote:The curve in the video looks like a rational function.
Suppose your x variable goes from 0 to 1.
Suppose you want to map this to y-values from 0 to 1.
Allow the midpoint x=0.5 to map to some y-valute t between 0 and 1.
So you have the following mapping table:
- Code: Select all
x y
-------
0 0
0.5 t
1 1
The general mapping formula would be:
y = t*x/(1 - t +(2t - 1)*x)
Obviously for t = 0.5 this results in the trivial mapping y = x as it should.
- shrunkyq
- Posts: 15
- Joined: Fri Aug 17, 2018 9:21 pm
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