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(RUBY) Splitting array into array of pairs
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(RUBY) Splitting array into array of pairs
Just a little line of code for those, that have an array of values they want to organize in pairs.
Say, you have this: [xvalue, yvalue, xvalue, yvalue, xvalue, yvalue, xvalue, yvalue, xvalue, yvalue]
will create [[xvalue, yvalue], [xvalue, yvalue], [xvalue, yvalue], [xvalue, yvalue], [xvalue, yvalue]]
You can have any length of the subarrays by adjusting the number of elements per slice, e.g. each_slice(3) == triplet
Just make sure to add the dummy map. each_slice just returns either an enumerator or nil, so it's needed. You can chain each_slice to create further layers.
Based on the example, will create
[[[xvalue, yvalue], [xvalue, yvalue]], [[xvalue, yvalue], [xvalue, yvalue]], [[xvalue, yvalue]]]
Happy Programming
Say, you have this: [xvalue, yvalue, xvalue, yvalue, xvalue, yvalue, xvalue, yvalue, xvalue, yvalue]
- Code: Select all
newarray = myarray.each_slice(2).map {|n| n}
will create [[xvalue, yvalue], [xvalue, yvalue], [xvalue, yvalue], [xvalue, yvalue], [xvalue, yvalue]]
You can have any length of the subarrays by adjusting the number of elements per slice, e.g. each_slice(3) == triplet
Just make sure to add the dummy map. each_slice just returns either an enumerator or nil, so it's needed. You can chain each_slice to create further layers.
- Code: Select all
newarray = myarray.each_slice(2).each_slice(2).map {|n| n}
Based on the example, will create
[[[xvalue, yvalue], [xvalue, yvalue]], [[xvalue, yvalue], [xvalue, yvalue]], [[xvalue, yvalue]]]
Happy Programming
"There lies the dog buried" (German saying translated literally)
- tulamide
- Posts: 2714
- Joined: Sat Jun 21, 2014 2:48 pm
- Location: Germany
Re: (RUBY) Splitting array into array of pairs
Just to add... to reverse the process simply use "flatten"
it will convert:[[xvalue, yvalue], [xvalue, yvalue], [xvalue, yvalue], [xvalue, yvalue], [xvalue, yvalue]]
to [xvalue, yvalue, xvalue, yvalue, xvalue, yvalue, xvalue, yvalue, xvalue, yvalue]
also it will convert: [[[xvalue, yvalue], [xvalue, yvalue]], [[xvalue, yvalue], [xvalue, yvalue]], [[xvalue, yvalue]]]
to [xvalue, yvalue, xvalue, yvalue, xvalue, yvalue, xvalue, yvalue, xvalue, yvalue]
Flatten also accepts an argument, which specifies the depth of flattening:
in this case: [[[xvalue, yvalue], [xvalue, yvalue]], [[xvalue, yvalue], [xvalue, yvalue]], [[xvalue, yvalue]]]
will be converted to: [[xvalue, yvalue], [xvalue, yvalue], [xvalue, yvalue], [xvalue, yvalue], [xvalue, yvalue]]
- Code: Select all
newArray=arrayOfPairs.flatten
it will convert:[[xvalue, yvalue], [xvalue, yvalue], [xvalue, yvalue], [xvalue, yvalue], [xvalue, yvalue]]
to [xvalue, yvalue, xvalue, yvalue, xvalue, yvalue, xvalue, yvalue, xvalue, yvalue]
also it will convert: [[[xvalue, yvalue], [xvalue, yvalue]], [[xvalue, yvalue], [xvalue, yvalue]], [[xvalue, yvalue]]]
to [xvalue, yvalue, xvalue, yvalue, xvalue, yvalue, xvalue, yvalue, xvalue, yvalue]
Flatten also accepts an argument, which specifies the depth of flattening:
- Code: Select all
newArray=arrayOfPairs.flatten(1)
in this case: [[[xvalue, yvalue], [xvalue, yvalue]], [[xvalue, yvalue], [xvalue, yvalue]], [[xvalue, yvalue]]]
will be converted to: [[xvalue, yvalue], [xvalue, yvalue], [xvalue, yvalue], [xvalue, yvalue], [xvalue, yvalue]]
- KG_is_back
- Posts: 1196
- Joined: Tue Oct 22, 2013 5:43 pm
- Location: Slovakia
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