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old sm SVF filter - anyone knows the hz to cutoff formula?

DSP related issues, mathematics, processing and techniques

old sm SVF filter - anyone knows the hz to cutoff formula?

Postby MichaelBenjamin » Mon Jun 15, 2020 1:45 pm

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Last edited by MichaelBenjamin on Mon Sep 21, 2020 10:30 am, edited 1 time in total.
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Re: old sm SVF filter - anyone knows the hz to cutoff formul

Postby martinvicanek » Mon Jun 15, 2020 7:42 pm

Corner frequency in Hz is roughly equal to samplerate*cutoff/2pi. But that's only valid for low cutoffs. For higher cutoffs the filter becomes weird and even unstable.

There is an SVF implementation which goes all the way up to Nyquist, search the forum for ZDF (zero delay feedback) filter.
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Re: old sm SVF filter - anyone knows the hz to cutoff formul

Postby MichaelBenjamin » Tue Jun 16, 2020 7:06 pm

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Last edited by MichaelBenjamin on Mon Sep 21, 2020 10:30 am, edited 1 time in total.
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Re: old sm SVF filter - anyone knows the hz to cutoff formul

Postby tulamide » Tue Jun 16, 2020 7:21 pm

martinvicanek wrote:Corner frequency in Hz is roughly equal to samplerate*cutoff/2pi. But that's only valid for low cutoffs. For higher cutoffs the filter becomes weird and even unstable.

There is an SVF implementation which goes all the way up to Nyquist, search the forum for ZDF (zero delay feedback) filter.

I understand that it has been solved otherwise. But I try to understand the answer.

sample rate = 44.1kHz
cutoff = 0.5

corner frequency = (roughly) 3500 Hz

But the user shall enter the cutoff as a frequency
cf = sr * c / 2pi
cf * 2pi = sr * c
c = cf * 2pi /sr (?)
I don't know cf, when user enters a cutoff of say 7000 Hz

I'm sure it's something simple that I don't see or messed up.
"There lies the dog buried" (German saying translated literally)
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