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Question: Trig function Sin1 and other
Question: Trig function Sin1 and other
How the sin1 is normalized?
-2Pi < x < 2PI -> sin
-1 < x < 1 -> sin1
I would like to understand how it is normallized.
I have not found a solution.
-2Pi < x < 2PI -> sin
-1 < x < 1 -> sin1
I would like to understand how it is normallized.
I have not found a solution.
Re: Question: Trig function Sin1 and other
0..1 for sin1 matchs 0..2*PI on regular sin
You can go below or above that range, it is always clipped to the valid range. So in general:
sin(2*PI*x) = sin1(x)
You can go below or above that range, it is always clipped to the valid range. So in general:
sin(2*PI*x) = sin1(x)
Re: Question: Trig function Sin1 and other
thank you, I think I'm lost in the calculations. 